((x^-7/8y^1/4)/(x^-3/8))^-8

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Solution for ((x^-7/8y^1/4)/(x^-3/8))^-8 equation: 


D( x )

x = 0

((((x^-7)/8)*y^1)/4)/((x^-3)/8) = 0

(x^-3)/8 = 0

x = 0

x = 0

((((x^-7)/8)*y^1)/4)/((x^-3)/8) = 0

((((x^-7)/8)*y^1)/4)/((x^-3)/8) = 0

((((x^-7)/8)*y)/4)/((x^-3)/8) = 0

1/4*x^-4*y = 0 // : 1/4*y

x^-4 = 0

x należy do O

(x^-3)/8 = 0

(x^-3)/8 = 0

1/8*x^-3 = 0 // : 1/8

x^-3 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(((((x^-7)/8)*y^1)/4)/((x^-3)/8))^-8 = 0

(((((x^-7)/8)*y)/4)/((x^-3)/8))^-8 = 0

65536*x^32*y^-8 = 0 // : 65536*y^-8

x^32 = 0

x = 0

x in { 0} 

x belongs to the empty set

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